Question

if x=√3+√2/√3-√2&y=√3-√2/√3+√2 then find the value of x^2+y^2
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Answer 1

Answer:

49-4√6

Step-by-step explanation:

x= ( √3 +√2)/( √3-√2)

x = [(√3+√2)(√3+√2)]/[(√3-√2)(√3+√2)]

x = (√3+√2)²/[(√3)²-(√2)²]

x = (√3+√2)²

x = (5 + 2√6) where the formula will be - (a+b)²=a²+b²+2ab

Similarly, it will be calculated as -

y = 5 - 2√6

Therefore,

x² = (5+2√6)²

= 25 + 24 + 4√6

= 49+4√6

y² =[5²-(2√6)²]

= 25+24-4√6

= 49-4√6

Thus the value is 49-4√6.