If x= (3/2)whole power 2 *(2/3)whole power-2 then find the value of x ki power -2
Answers
Answered by
1
Answer:
x=(2/3)^8
Step-by-step explanation:
x=(3/2)^2*(2/3)^-2
so x = ((3/2)^2*(2/3)^-2)^-2 now
on multipling power inside we get
x = ((3/2)^-4*(2/3)^4) => ((2/3)^4*(2/3)^4)
thus
x=(2/3)^8
Answered by
0
Answer:
Step-by-step explanation:
x=(3/2)^2*(2/3)^-2
so x = ((3/2)^2*(2/3)^-2)^-2 now
on multipling power inside we get
x = ((3/2)^-4*(2/3)^4) => ((2/3)^4*(2/3)^4)
thus
x=(2/3)^8
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