Math, asked by shagun684, 1 year ago

If x= (3/2)whole power 2 *(2/3)whole power-2 then find the value of x ki power -2

Answers

Answered by laksh2525424
1

Answer:

x=(2/3)^8

Step-by-step explanation:

x=(3/2)^2*(2/3)^-2

so x = ((3/2)^2*(2/3)^-2)^-2 now

on multipling power inside we get

x = ((3/2)^-4*(2/3)^4) => ((2/3)^4*(2/3)^4)

thus

x=(2/3)^8

Answered by angelabinoy07
0

Answer:

Step-by-step explanation:

x=(3/2)^2*(2/3)^-2

so x = ((3/2)^2*(2/3)^-2)^-2 now

on multipling power inside we get

x = ((3/2)^-4*(2/3)^4) => ((2/3)^4*(2/3)^4)

thus

x=(2/3)^8

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