Question

(SecA-tanA)*2=1-sinA/1+sinA

Answer 1

Answer:

(1/cosa-sina/cosa) ^2

(1-sina) ^2/cis^2a

(1-sina) ^2/(1-sina) (1+sina)

then 1-sina/1+sina

Answer 2

$(secA { - tanA})^{2} \\ \\ = ( \frac{1}{cosA} - \frac{sinA}{cosA} ) ^{2} \\ \\ = \frac{( {1 - sinA})^{2} }{ {cos}^{2} A} \\ \\ = \frac{( {1 - sinA})^{2} }{1 - {sin}^{2} A} \\ \\ = \frac{1 - sinA}{1 + sinA}$