Question

If (x + 3)2 + (y - 2)2 = 0, then xy =____​

Answer 1

(x+3)2 = 2x + 6 ; (y-2)2 = 2y - 4. So, (x+3)2 + (y-2)2 = 0 ; 2x+6 + 2y -4 = 0; . 2x + 6 + 2y = 0+4 ;
2x + 6 + 2y = 4; 2x + 2y = 4-6; 2x+2y = -2; 2x = -2/2 ; 2x = -1. 2y = -2/2 ; 2y = -1. Thefore x = -1, y = -1. xy = x x y = -1 x -1 = 1. Thefore xy = 1.
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