Question

if x=3 is one root of the equation is X2-2kr-6=0 then find the value of k

Answer 1

all the bst fr ur xm

Answer 2

(3)2 -2k(3)-6=0
9-6k-6=0
9-6k=6
-6k=6-9
-6=-3
k=3÷6
1/2