if x=3 is one root of the equation is X2-2kr-6=0 then find the value of k
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all the bst fr ur xm
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yash1004:
thnx
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(3)2 -2k(3)-6=0
9-6k-6=0
9-6k=6
-6k=6-9
-6=-3
k=3÷6
1/2
9-6k-6=0
9-6k=6
-6k=6-9
-6=-3
k=3÷6
1/2
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