if x=3 is one root of the quadratic equation x square minus 2kx minus six =0
Answers
Answered by
2
put x=3 in equation
x²-2kx-6=0
(3)²-2k(3)-6=0
9-6k-6=0
-6k=-9+6
-6k=-3
Sign of minis(-) will be cut out
6k=3
k=3/6
k=1/2
hope it is helpful
pls mark it as brainliest
x²-2kx-6=0
(3)²-2k(3)-6=0
9-6k-6=0
-6k=-9+6
-6k=-3
Sign of minis(-) will be cut out
6k=3
k=3/6
k=1/2
hope it is helpful
pls mark it as brainliest
Alfaizalishaikh:
your answer is wrong because the square of 3 is 9 not 27
Answered by
1
3square minus 2k×3-6=0
9-6k-6=0
6k=3
k=1/2
9-6k-6=0
6k=3
k=1/2
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