Question

if x = 3 is one root of the quadratic equation x²-2kx-6=0, then find the value of k​

Answer 1

Answer:

Step-by-step explanation:

As x=3 is root of the quadratic equation....thus putting value of x in eq.

(3)²-2k(3)-6=0

9-6k-6=0

3-6k=0

3=6k

k=3/6

k=1/2

Answer 2

Answer:

$\huge\mathfrak\orange{Answer\:is\:\frac{1}{2}}$

On substituting x we get

$3^{2}-2k(3)-6=0$

$9-6k-6=0$

$6k=3$

$k=\frac{1}{2}$