Question

If x=3 is one root of the quadratic equation x²-2px-6 the find the value of p

Answer 1

Answer:

p=1/2

Step-by-step explanation:

give x=3 is one root of Q.E

q(x)=x^2-2px-6

as x is 3 when

x^2-2px-6=0

when substituting

9-6p-6=0

3=6p

p=1/2

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Answer 2

Answer:

$\huge\boxed{\bigstar\:\:\:p=\frac{1}{2}\:\:\:\bigstar }$

Step-by-step explanation:

✢ Given:-

   3 is a root of Quadratic Equation x²-2px-6=0.

✢ To Find:-

   The Value of p.

✢ Solution:-

    p(x)=x²-2px-6=0

 Putting 'x'=3, we get:

⇒ p(3)=(3)²-2p(3)-6=0

⇒ 9-6-6p=0

⇒ 3=6p

$\implies p=\frac{3}{6}$

$\implies\boxed{p=\frac{1}{2} }$

∴ The Value of p satisfying this Quadratic Equation is $\huge{\frac{1}{2} }$.