Question

if x=3+root8 and y=3-root8 then 1/x square +1/y square=

Answer 1

x=3+√8 and y=3-√8

then,
(1/x)²+(1/y)²=( x²+y²)/(xy)²
and
using a²-b²=(a-b)(a+b);

={(9+8+6√8)+(9+8-6√8)}/(9-8)²
=34/1

Answer 2

Answer:

Step-by-step explanation:

x=3+√8 and y=3-√8

then,

(1/x)²+(1/y)²=( x²+y²)/(xy)²

and

using a²-b²=(a-b)(a+b);

={(9+8+6√8)+(9+8-6√8)}/(9-8)²

=34/1