if x^4 + 1 = 1297 AND y^2 - 1 = 2400, find y^2 - x^2
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Answered by
9
Given (correct values)
- x⁴ + 1 = 1297
- y⁴ - 1 = 2400
To find
- y² - x²
Solution
- x⁴ + 1 = 1297
- x⁴ = 1296
- x⁴ = 6⁴
⇾ Bases are same equate the power
- x = 6
➝ The value of x is 6
- y⁴ - 1 = 2400
- y⁴ = 2401
- y⁴ = 7⁴
⇾ Bases are same equate the power
- y = 7
➝ The value of y is 7
To find
- y² - x²
- (y + x) (y - x) (a² - b²) = (a + b) (a - b)
- (7 + 6) ( 7 - 6)
- (13)(1)
- 13
➝ The value of y² - x² is 13
Answered by
2
x⁴ + 1 = 1297
y⁴ - 1 = 2400
To find
y² - x²
Solution
x⁴ + 1 = 1297
x⁴ = 1296
x⁴ = 6⁴
⇾ Bases are same equate the power
x = 6
➝ The value of x is 6
y⁴ - 1 = 2400
y⁴ = 2401
y⁴ = 7⁴
⇾ Bases are same equate the power
y = 7
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