If x = 4/3 is a root of polynomial f(x) = 6xcube-11xsquare+kx-20. Find the value of k pls help its urgent
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Hi ....dear...
here is your answer...
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Putting x=4/3 ..in polynomial .. will satisfy the equation.
we obtain f(4/3) = [6* (4/3)3] - [ 11* (4/3)2 ] + k*4/3 -20 = 0
=128/9 - 176/9 + 4k/3 - 20 =0
=(124+12k)/9 = 0
=124 + 12k = 0
=12 k = -124
=k = -31/3
here is your answer...
---------------------------------------------------------------------
Putting x=4/3 ..in polynomial .. will satisfy the equation.
we obtain f(4/3) = [6* (4/3)3] - [ 11* (4/3)2 ] + k*4/3 -20 = 0
=128/9 - 176/9 + 4k/3 - 20 =0
=(124+12k)/9 = 0
=124 + 12k = 0
=12 k = -124
=k = -31/3
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