Math, asked by rakesh2265, 10 months ago

if (x - 4) is the mean proportional of (x- 5) and( x- 2) then find the value of x​

Answers

Answered by Lipsa133
2

Step-by-step explanation:

{(x-5)+(x-2)}/2=(x-4)

=>(2x-7)/2=(x-4)

=>2x-7=2x-8

I think your question is wrong ...

so please send correct question...

Answered by pulakmath007
3

If (x - 4) is the mean proportional of (x - 5) and( x - 2) then value of x = 6

Given :

(x - 4) is the mean proportional of (x - 5) and( x - 2)

To find :

The value of x

Solution :

Solution :Step 1 of 2 :

Form the equation

Here it is given that (x - 4) is the mean proportional of (x - 5) and( x - 2)

By the given condition

\displaystyle \sf{  \frac{x - 5}{x - 4}  =  \frac{x - 4}{x - 2}  }

Step 2 of 2 :

Find the value of x

\displaystyle \sf{  \frac{x - 5}{x - 4}  =  \frac{x - 4}{x - 2}  }

\displaystyle \sf{ \implies    {(x - 4)}^{2}  = (x - 5)(x - 2) }

\displaystyle \sf{ \implies     {x}^{2} - 8x + 16  = {x}^{2}  - 5x - 2x + 10}

\displaystyle \sf{ \implies     {x}^{2} - 8x + 16  = {x}^{2}  - 7x + 10}

\displaystyle \sf{ \implies      - 8x +7x  = 10 - 16}

\displaystyle \sf{ \implies      - x  =  - 6}

\displaystyle \sf{ \implies   x  =   6}

Hence the required value of x = 6

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