If x+5 is a mean proportion between x+2 and x+9, find the value of x
Answers
Answered by
71
x+5=root(x+2)(x+9)
squaring on both sides
(x+5)^2=(x+2)(x+9)
x^2+10x+25 =x^2+11x+18
10x+25=11x+18
11x-10x=25-18
x=7 is answer
squaring on both sides
(x+5)^2=(x+2)(x+9)
x^2+10x+25 =x^2+11x+18
10x+25=11x+18
11x-10x=25-18
x=7 is answer
Answered by
15
hlo frd here is your ans ........
first i want to tell u about basic information about mean proportion .........
mean proportion of two number X and Y Is Z Then a relation is occurred which is
_____ XY = Z^2
now in our questions
there X+5 is mean proportion then
(x+2)(x+9)=(x+5) ^2
♦️♦️♦️ therefore ×^2+11x+18=x^2+10x+25
7=x
hence x= 7
BE BRAINLY.
first i want to tell u about basic information about mean proportion .........
mean proportion of two number X and Y Is Z Then a relation is occurred which is
_____ XY = Z^2
now in our questions
there X+5 is mean proportion then
(x+2)(x+9)=(x+5) ^2
♦️♦️♦️ therefore ×^2+11x+18=x^2+10x+25
7=x
hence x= 7
BE BRAINLY.
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