Question

if (x+7954*7956) be a square number then the value of x is

Answer 1

$x + 7954 \times 7956 = {y}^{2} \\ x + (7955 - 1)(7955 + 1) = {y}^{2} \\ x + {7955}^{2} - {1}^{2} = {y}^{2}$
if x is 1 then y2 will be a perfect square
therefore x =1