Question

If (x + a)^2 + b = x^2 + 6x + 10, find the values of a and b.​

Answer 1

$= > {(x + a)}^{2} + b = {x}^{2} + 6x + 10 \\ = > {x}^{2} + 2ax + {a}^{2} + b = {x}^{2} + 6 x+ 10 \\ = > 2a = 6 (comparing the coefficients of x) \\ = > a = 3 \\ = > b = 10( comparing constant)$

Hope you get it