the base of an isosceles traingle is 16 cm and its area is 48 cm^2 find the perimeter
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Base - 16cm
Area - 48cm^2
Height -?
Measure of one side - ?
Perimeter - ?
We are only given with base and the area...
we need to find the height of the triangle...
: 1/2*base*height=area of a triangle
so, 1/2*16*H=48
H = 6cm^2
Now we need to find the measure of any one side , it is an isosceles triangle so the length of both the sides measure the same...
If we divide the triangle in 2 parts, we get 2 right angled triangles
Base of each triangle = 8cm
Now, the sides of the isosceles triangle now become hypotenuse of a right angled triangle...
Hypotenuse = A^2 + B^2
So, A= 8cm
B= 6cm
Now hypotenuse = 8^2+6^2 = 64+36=10^2
= 10Cm of one side
2 sides = 20cm
perimeter = 20+16
=36cm
so, the perimeter of the triangle is 36 cm
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