Question

If (x+a)(x+b)(x+c) = x^3+14x^2+59x+70,find the value of
1.a+b+c
2.1/a+1/b+1/c
3.a^2+b^2+c^2
4.a/bc+b/ac+c/ab

Answer 1

Answer:

1.a+b+c=14

Step-by-step explanation:

open all the brackets and compare the coefficients of x^2

Answer 2

Step-by-step explanation:

$(x + a)(x + b)(x + c) = {x}^{3} + 14 {x}^{2} + 59x + 70 \\ now \\ (x + a)(x + b)(x + c) \\ ( {x}^{2} + ax + bx + ab)(x + c) \\ {x}^{3} + a {x}^{2} + b {x}^{2} + c {x}^{2} + abx + abc \\ {x}^{3} + (a + b + c)x + abx + abc \\ now \: compare \: the \: equation \\ \\ (a + b + c) = 14 \\ ab = 59 \\ abc = 70$

by this method we calculate the value of ( a + b + c) and father we can calculate the values of any algebraic equation.