If x and y are both odd positive integers then x square + y square is even but not divisible by 4
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Step-by-step explanation:
Let the two odd positive numbers be
X=2k+1 and Y=2p+1
Hence X^2+Y^2=(2k+1)^2+(2p+1)^2
=4k^2+4k+1+4p^2+4p+1
=4k^2+4p^2+4k+4p+2
=4(k^2±p^2+k+p)+2
Therefore, clearly notice that the sum of square is even the number is not divisible by 4
Hence if X and Y are odd positive integers, X^2+Y^2 is even but not divisible by 4.
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