If x and y are complementary angles,then sin x=sin y tanx=tany cosx=cosy secx=cosecy
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Answered by
274
x and y are complementary => x + y = 90°
=> sin x = sin (90° - y) = cos y
=> sin y = cos(90 - x) = cos x
Also, tan y = Cot (90 - y) = Cot x
sec x = Cosec (90 - x) = cosec y
sin y * tan x = cos x * sinx/cos x = sin x
tan y * cos x = cot y * cos x = cos y / sin y * sin y
= cos y = sin x
cosec y = 1/siny = 1/cosx = sec x
=> sin x = sin (90° - y) = cos y
=> sin y = cos(90 - x) = cos x
Also, tan y = Cot (90 - y) = Cot x
sec x = Cosec (90 - x) = cosec y
sin y * tan x = cos x * sinx/cos x = sin x
tan y * cos x = cot y * cos x = cos y / sin y * sin y
= cos y = sin x
cosec y = 1/siny = 1/cosx = sec x
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Answered by
14
Answer:
Step-by-step explanation:
sec x= cosec y is the right option
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