If x and y are the two digits of the number 653xy such that this number is divisible by 80, then what is x + y = ?
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If a number is divisible by a number, is it always divisible by factors of that number.
Since 10 is a factor of 80, 653xy is divisible by 10. It means last digit,y =0
Rewriting 653xy as 653x0. Since 8 is a factor of 80, 653x0 is divisible by 8. It means last three digits 3x0 is divisible by 8. Hence, x is 2 or 6
if x=2, number is 65320. But this is not divisible by 80
if x=6, number is 65360 which is divisible by 80
Therefore number is 65360 with x=6 and y=0.
x+y = 6+0 = 6
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