Question

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Answer 1

Step-by-step explanation:

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Answer 2

Your question: a / x-b + b / x-a = 2  

a(x-a) + b(x-b) / (x-a)(x-b) = 2  

ax - a" + bx - b" = 2 (x-a) (x-b)  

ax - a" + bx - b" = (2x-2a) (x-b)  

ax - a" + bx - b" = 2x" - 2bx - 2ax + 2ab  

-2x" + 3bx + 3ax - a" - b" - 2ab = 0  

2x" - 3bx - 3ax + a" + b" +2ab = 0  

2x" - 3 (a+b) x + (a+b)" = 0  

2x" - 2(a+b)x - 1(a+b)x + (a+b)" = 0  

2x [x - (a+b)] - (a+b) [x - (a+b)] = 0  

(2x - a - b ) (x - a - b) = 0  

Thus, either -  

2x - a - b = 0  

Therefore x = a+b / 2  

or -  

x - a - b = 0  

Therefore x = a + b