If x is equal to 2 minus under root 3 find the value of x minus one by X whole cube
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Answered by
9
x = 2 + √3
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
Answered by
5
x=2-root 3
x-(1/x)^3 =?
2-
x-(1/x)^3 =?
2-
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