Question

If x plus one upon X equal to root 3 find x cube + 1 upon x cube

Answer 1

$x + \frac{1}{x} = \sqrt{3} \\ \\ \\ (x + \frac{1}{x})^{3} = ({ \sqrt{3 }})^{3} = \sqrt{3} \times( { \sqrt{3} })^{2} \\ \\ 3\sqrt{3}$

Answer 2

$\underline{\underline{\bold{SOLUTION:}}}$

Given that,

$x + \frac{1}{x} = \sqrt{3}$

Now, $x^{3} + \frac{1}{x^{3}}$

$=(x+\frac{1}{x})^{3} - (3*x*\frac{1}{x})(x+\frac{1}{x})$

= (√3)³ - 3 (√3)

= 3√3 - 3√3

= 0