plz!!!!!!!!! answer this question with explaination!!!!!urgent!!!!!!!!
Answers
Answer:0.55
Step-by-step explanation:
I think it is the correct answer divide the initial value by 2 and then divide by 1
Answer:
Answer option 1. that is 0.74 seconds.
Step-by-step explanation:
Stone initial speed = u = 5 m/s
Speed on the top = v = 0 m/s.
Acceleration = acceleration due to gravity = g = 9.8 m/sec²
From the laws of motion, we have
v² – u² = 2as
Substituting above values, we get
-25 = -2*g*s
S = 25/2g meters.
Time taken by upward journey is calculated by
v = u + at
0 = 5 - gt
t = 5/g
Since the stone was thrown from 1 meter above ground, while coming back, the stone should reach s+1 meters to come to ground.
Now from the top point, u = 0 a = g.
s = ut + at²/2
(25/2g) + 1 = 0 + gt²/2
25/g + 2 = gt²
t² = 25/g² + 2/g = (25+2g)/g²
t = √(25+2g)/g
Total time taken for first stone to reach groud = 5/g + SQRT(25+2g)/g
= 0.51 + 0.68 = 1.19.
for second stone to be dropped from 1m height, the time taken is calculated
s = ut + at²/2
1 = 0 + gt²/2
t² = 2/g
t = √(2/g) = 0.45 sec.
So second stone should be dropped after 1.19 – 0.45 = 0.74 seconds.