if x- root 2 is a factor of x4-x²+7k find the value of k
Answers
Answered by
1
Answer:
Step-by-step explanation:
let p(x) = x^4 - x^2 + 7k
x- root 2 is a factor of p(x)
so x= root 2 is a zero of p(x)
so p(root 2) = 0
=> (root 2)^4 - (root 2)^2 + 7k =0
=> 4 - 2 +7k =0
so 7k = -2
or k= (-2)/7
Answered by
0
Answer:
x=✓2
when we subitute this in the equation we get
✓2^4-✓2^2+ 7k=0
4-2+7k=0
2+7k=0
k=-2/7
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