Question

If x=secθ+tanθ and y=secθ−tanθ , then
1)
$xy = 1$
2)
${x}^{2} + {y}^{2} = 1$
3)
${x}^{2} + y = 1$
4)
$\frac{x + y}{xy} = 1$
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Answer 1

Answer:

option 1

Step-by-step explanation:

xy = (secθ+tanθ)(secθ-tanθ)

= sec^2θ - tan^2θ

= 1