Question

If x=secθ+tanθx=secθ+tanθ  and y=secθ−tanθy=secθ−tanθ , then
A. xy = 1
B. x^2 + y^2 = 1
C. x^2 + 1 = y
D. x + y / xy = 1​

Answer 1

Answer:

B option is correct answer