if X square + 8 x minus 7 is equals to zero then find the value of x + 4 whole square
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x^2+8x-7=0
x^2+7x+x-7=0
x(x+7)-1(x+7)
(x+7)(x-1)
x=-7,1
x=1
(x+4)^2
(1+4)^2
5^2
25
x^2+7x+x-7=0
x(x+7)-1(x+7)
(x+7)(x-1)
x=-7,1
x=1
(x+4)^2
(1+4)^2
5^2
25
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