Please help me guy's
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Hey there! .
( i ) 4Na + O2 --------> 2Na2O
Sodium on reacting with Oxgyen forms Sodium Oxide.
We know that, Addition of Oxygen is oxidation.
So, Na is getting oxidised.
( i i )
CuO + H2 -------> Cu + H2O.
Here, Cu is getting reduced
H2 is getting oxidized.
Hope you are helped!
( i ) 4Na + O2 --------> 2Na2O
Sodium on reacting with Oxgyen forms Sodium Oxide.
We know that, Addition of Oxygen is oxidation.
So, Na is getting oxidised.
( i i )
CuO + H2 -------> Cu + H2O.
Here, Cu is getting reduced
H2 is getting oxidized.
Hope you are helped!
Babukijaan:
thanks
Answered by
1
In (I) Na is oxidized
In (II) CuO is reduced to Cu
and hydrogen is oxidized to water
In (II) CuO is reduced to Cu
and hydrogen is oxidized to water
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