Question

if x= tan1 ,y=tan2,z=tan3 then the descending order is​

Answer 1

tan 1 > tan 3 > tan 2 ; hence x > z > y

Step-by-step explanation:

0 < 1 < π/2, so 1 radian is in quadrant one.

sin 1 > 0 ; cos 1 > 0 ; tan 1 > 0

π/2 < 2 < π, so 2 radians is in quadrant two.

sin 2 > 0 ; cos 2 < 0 ; tan 2 < 0

2 < 3 < π, so 3 radians is in quadrant three.

sin 3 > 0 ; cos 3 < 0 ; tan 3 < 0

π - 3 is a very small number, so sin 3 is much closer  to 0 than sin 2. Hence tan 3 is also much closer to 0.

So tan 1 > tan 3 > tan2  

Therefore x > z > y

Answer 2

If x = tan 1 ,y = tan 2,z = tan 3 then the descending order is​

z > y > x

Step-by-step explanation:

Given:

x = tan 1

y = tan 2

z = tan 3

To find out:

The descending order of x, y, z

Solution:

We know that $\tan A$ is an increasing function

i.e. as the value of A increases, the value of $\tan A$ also increases

Therefore, we can easily say that

$\tan 3>\tan 2>\tan 1$

or, $z>y>x$

Hope this answer is helpful.

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