Question

If x upon y plus y upon x is equals to minus 1 (x,y is not equals to zero) then find the value of x cube minus y cube

Answer 1

$\therefore x^3-y^3$=0

Step-by-step explanation:

Given,

$\frac{x}{y} +\frac{y}{x}= -1$

$\Rightarrow \frac{x^2+y^2}{xy} =-1$

$\Rightarrow x^2+y^2=-xy$

$\therefore x^3-y^3$                

$=(x-y)(x^2+y^2+xy)$

$=(x-y)(-xy+xy)$            $[\because x^2+y^2=-xy]$

$=(x-y)\times 0$

=0          

Answer 2

Step-by-step explanation:

refer to the attachment

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