Math, asked by shashanknagar5882, 10 months ago

The temperature of an iron piece is heated from 30 degree celsius to 90 degree celsius. what is the change in its temperature on the fahrenheit scale and on the kelvin scale​

Answers

Answered by santy2
9

Answer:

The temperature of an iron piece is heated from 30 degree Celsius to 90 degree Celsius. The change in its temperature on the Fahrenheit scale and on the kelvin scale​ is 92 F and 333 K respectively.

Step-by-step explanation:

Let's first get the change in temperature.

Change in temperature = Final temperature - initial temperature

This equals to:

= 90 - 30 = 60°

We need to write this in Fahrenheit and Kelvin scale.

The conversions are as follows:

0° C = 273 Kelvins

0° = 32 Fahrenheit

From the given conversion rates, we write down the change in temperature as:

In Kelvin = 273 + 60 = 333 K

In Fahrenheit = 32 + 60 = 92 F

Answered by Tulsi4890
11

       If the temperature of an iron piece is heated from 30 degree Celsius to 90 degree Celsius, The change in its temperature on the Fahrenheit scale and on the Kelvin scale will be 140°F and 333.15 K respectively.

  • The change in temperature in Celsius will be = Current Temperature - Previous temperature
  • So, 90 degree Celsius- 30 degree Celsius = 60 degree Celsius
  • Change in temperature in Kelvin scale = Temperature in Celsius + 273.15 = 60 + 273.15 = 333.15 K
  • Change in Temperature in Fahrenheit scale = (60°C × 9/5) + 32 = 140°F
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