If x:y= 1: 3, y:z= 5: k, z:t= 2: 5 and t:x= 3: 4 then what is the value of k?
Answers
Answer:
k = 1/2
Step-by-step explanation:
As we know,
If a:b = N1 : D1,
b:c = N2:D2,
c:d = N3:D3
then we can write =>
a : b : c : d = N1*N2*N3 : D1*N2*N3 : D1*D2*N3 : D1*D2*D3 ----eq(1)
from eq(1)
x : t = 1*5*2 : 3*k*5
x:t = 10 : 15*k
x:t = 2 : 3k
4:3 = 2/k : 3
from here,
2/k = 4
1/k = 2
k = 1/2
just practise this trick and you can find any solutin of this type of question.
Given:
To find: The value of
Solution: According to the given question,
Using cross multiplication:
∵ ...(1)
also, [Given]
i.e., ...(2) [Using cross multiplication]
[Given]
i.e., ...(3) [Using cross multiplication]
[Given]
i.e., ...(4) [Using cross multiplication]
Now, using (1) and (4)
∵
i.e.,
∴ ...(5)
It can be written as:
∵
From (3),
∴
Now, putting in equation (2)
⇒
⇒
⇒
Hence, the value of is .