Question

*If x/y = 2/3 then 2x² + 3y² / 2x² - 3y² = ?*

1️⃣ 35/19
2️⃣ 19/35
3️⃣ -19/35
4️⃣ -35/19​

Answer 1

Step-by-step explanation:

4. 2x^2+3y^2/2x^2-3y^2

= 2(2/3y)^2+3y^2/2(2/3y)^2-3y^2

= 35/9y^2/(-19)/9y^2

= -35/19