If x-y=5and xy=84,find the value of xcube-ycube
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Answered by
216
Given :
x-y=5
xy=84
RTP :
By using the formula :
(x-y)³=x³-y³-3x²y+3xy²
x³-y³=(x-y)³+3x²y-3xy²
=(x-y)³+3xy[x-y]
by substituting the values, we get :
=[5]³+3x84[5]
=125 +1260
=1385
∴ x³-y³=1385
x-y=5
xy=84
RTP :
By using the formula :
(x-y)³=x³-y³-3x²y+3xy²
x³-y³=(x-y)³+3x²y-3xy²
=(x-y)³+3xy[x-y]
by substituting the values, we get :
=[5]³+3x84[5]
=125 +1260
=1385
∴ x³-y³=1385
Answered by
127
Hi friend,
Refer to the pic.
Hope it helped!!
Refer to the pic.
Hope it helped!!
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