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If x - y = 6 and xy = 10 find the value of x^2 + y^2
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Answer:
Given,
x + y= 6 (equation 1)
x - y = 4 (equation 2)
Squaring and adding both the equations,
(x + y)² + (x - y)² = 6² + 4²
=> x² + y² + 2xy + x² + y² - 2xy = 52
=> 2(x²+y²) = 52
=> x²+y²=26
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