Question

If (x/y)^n-1 = (y/x)^n-3, then n=?

Answer 1

( x /y) ^( n -1) = ( y/x )^( n -3)

(x /y)^( n -1) = (x/y)^{ -(n -3)}

( x/y)^( n -1) = (x/y)^(3 -n )

we know,
a^m = a ^n
then
m = n

use this here ,
so,
n -1 = 3 -n

2n = 4

n =2 ( answer)