If (x/y)^n-1 = (y/x)^n-3, then n=?
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( x /y) ^( n -1) = ( y/x )^( n -3)
(x /y)^( n -1) = (x/y)^{ -(n -3)}
( x/y)^( n -1) = (x/y)^(3 -n )
we know,
a^m = a ^n
then
m = n
use this here ,
so,
n -1 = 3 -n
2n = 4
n =2 ( answer)
(x /y)^( n -1) = (x/y)^{ -(n -3)}
( x/y)^( n -1) = (x/y)^(3 -n )
we know,
a^m = a ^n
then
m = n
use this here ,
so,
n -1 = 3 -n
2n = 4
n =2 ( answer)
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