If x/y + y/x= -1 find the value of x^3 - y^3
Answers
Answered by
4
If x/y+y/x=-1
Thenx^3-y^3=0
Solution
We know that x^3-y^3= (x-y)(x^2+xy+y^2)
Now solve x/y+y/x
> x^2+y^2/xy=-1
> x^2+y^2=-xy
Now put the value for x^3-y^3
(x-y)(-xy+xy) [cz x^2+y^2=-xy]
(x-y)(0)
0 = answer
Similar questions