Question

if x^y = y^x, then [x/y]^x/y is equal to

Answer 1

$(x/y)^{x/y}$

[tex] x^{x/y} /y^{x/y} [/tex]

$x^{x/y} /y^{x}(^{1/y})$

Taking from question,

$x^{y} = y^{x}$

Then,

$x^{x/y} / x^{y}(^{1/y})$

And so,

$x^{x/y} / x^{1}$

$x^{x/y - 1}$

$x^{x-y/y }$
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