If x+y+z=0 find th value of x^3+y^3+z^3
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Answer:
If x + y + z = 0
then the value of x^3 +y^3 + z^3 is 3xyz.
Explanation:
x^3 + y^3 + z^3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Putting x + y + z = 0
x^3 + y^3 + z^3 – 3xyz = (0) (x2 + y2 + z2 – xy – yz – zx)
x^3 + y^3 + z^3 – 3xyz = 0
∴, x^3 + y^3 + z^3 = 3xyz
Hope it helps!
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