Question

If x +y+z=9 and xy+yz+xz=26 find the value of x^2+y^2+z^2

Answer 1

Answer:

Step-by-step explanation:

Give thanx tme

Answer 2

Answer:

x+y+z=9  

Squaring both sides  of the above equation we get,

x²+y²+z²+2(xy+yz+zx)=81

Substitute values of xy+yz+zx which is 26

So

x²+y²+z²=29

Hope you get your answer.