Math, asked by samsulalam2726, 10 months ago

If x+y+z=9,then find the value of (3-x)^3 + (3-y)^3 + (3-z)^3 - 3(3-x)(3-y)(3-z)

Answers

Answered by Anonymous
0
questions is not correct
we can assume anything means different answers
let x=2, y=3,z=4
(3-2)^3 +(3-3)^3 +(3-4)^3 -3(3-2)(3-3)(3-4)

=2^3 +0^3 + -1^3 - 3(1)×(0)×(-1)
=8-1
=7


x=3,y=3,z=3

answer=0

there should be value of ab+bc+ca to get right answer.


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