Question

if x,y,z are digits such that (100x+10y+z)(x+y+z)=2005,then find x,y,z. (only a ace can find)​

Answer 1

Answer:

we know that from 2 to 9 2005 is divisble by only 5,

so that we have x+y+z = 5

so that 2005/5 = 401

we have to set 100x+10y+z this equation that this value is = 401

x+y+z = 5

100x + 10y + z = 401

put x=4, y=0,z=1 that satisfy both equation..

(100*(4) + 10*(0) + 1 ) * (4+0+1) = 401*5 =2005