if x²+1/x²=38 find the value of x-1/x
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Answered by
30
x²+1/x²=38
=>(x-1/x)^2+2.x.1/x=38
=>(x-1/x)^2=36
=>(x-1/x)=√36
=+-6
I hope it helps you
=>(x-1/x)^2+2.x.1/x=38
=>(x-1/x)^2=36
=>(x-1/x)=√36
=+-6
I hope it helps you
Answered by
80
Given ,
⇒ x² + 1 / x² = 38.
We have to find the value of x - 1 / x.
⇒ ( x - 1/x )² = x² + 1/x² - 2 * x * 1/x
⇒ ( x - 1/x )² = x² + 1/x² - 2
By substituting the value of ( x² + 1/x² ) in above equation ,
⇒ ( x - 1/x )² = 38 - 2
⇒ ( x - 1/x )² = 36
⇒ ( x - 1/x ) = √36
∴ ( x - 1/x ) = ±6.
So, ( x - 1/x ) = ±6.
⇒ x² + 1 / x² = 38.
We have to find the value of x - 1 / x.
⇒ ( x - 1/x )² = x² + 1/x² - 2 * x * 1/x
⇒ ( x - 1/x )² = x² + 1/x² - 2
By substituting the value of ( x² + 1/x² ) in above equation ,
⇒ ( x - 1/x )² = 38 - 2
⇒ ( x - 1/x )² = 36
⇒ ( x - 1/x ) = √36
∴ ( x - 1/x ) = ±6.
So, ( x - 1/x ) = ±6.
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