Question

If(x²+px-30)= (x-5)(x+6) Then the value of P Is
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Answer 1

Answer: p=1

Step-by-step explanation:>(x^2 +px -30)=x^2 +6x -5x -30

> Px= +x

>P=1

Answer 2

The value of p =1.

Step-by-step explanation:

Given : $(x^2+px-30)= (x-5)(x+6)$  (1)

Let -5 =a and 6=b

Then by using identity : $(x+a)(x+b)=x^2+(a+b)x+ab$ , we have

$(x-5)(x+6)=x^2+(-5+6)x+(-5)(6)\\=x^2+x-30$

Substituting the value of $(x-5)(x+6)$ in (1), we get

$(x^2+px-30)= (x^2+x-30)$

On comparing the coefficient of x , we get

p=1

Hence, the value of p =1.

Learn more :

If x-1 is a factor of x⁴-5x³+5²+px-6 then the Value of p is

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