Question

if x²+y²=26 and xy=3 find the value of x⁴+y⁴

Answer 1

it is correct answer thanks me

Answer 2

x^2 + y^2 = 26
x y = 3
squaring both sides
x^2 y ^2 = 9
( x ^2 + y^2)^2 = x^4 + y^4 + 2x^2 y^2
26 ^2 = x^4 + y^4 + 2 (9)
676 - 18 = x^4 + y^4
x^4 + y^4 = 658

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