Question

if x²+y²=z² show that logz-y + logz+y = 2
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Answer 1

Answer: - 2

     Step-by-step explanation:  the answer is 2

=log z-y base x+ log z+y base x

=(log z-y base x)+ (log z+y base x)

=log z-y*z+y

=log z²-y² (x² + y² = z² ) ( x² = z²- y²)

=lod x² base x.

= 2 log x base x ( log x base x = 1)

= 2