Question

If xcosec²30°sec²45°/8cos²45°sin²60°= tan260° – tan230° then
A. 1
B. - 1
C. 2
D. 0

Answer 1

$\huge\mathbb{\underline{SOLUTION:-}}$

here given

sin θ + cos θ = √2

we have to find

tanθ + cot θ =?

• sin θ + cos θ = √2

now square on both side

• = ( sin θ + cos θ )² = √2²

• = (sin² θ + cos² θ )+ 2 sin θ cos θ = 2
• = 1+ 2sin θ cos θ = 2
• => sin θ cos θ = 1/2

now

• tanθ + cot θ =sin θ/cos θ + cos θ/sin θ
• =( sin² θ +cos² θ) / sin θ cos θ

= 1 / (1/2) = 2 answer

Answer 2

Answer:

Refer to the attachment