If XY bisect angle MXN = 72⁰, then value of angle MXY will be what? please tell
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Let the equations
y=m
1
x=0 and y=m
2
z are two straight lines represented by the given pair of straight line equations.
m
1
=tanα and m
2
=tanβ and β>α
Hence,
(y−m
1
)(y−m
2
)=y
2
=
b
2h
xy+
b
a
x
2
so,
m
1
−m
2
=
a
2b
and m
1
m
2
=
b
a
If θ be the angle subtended by angle bisector (y=mx) of the pair of straight line with the positive direction of x-axis, then m=tanθ
Now it is obvious that
θ−α=β−θ
So,
α+β=2θ
⇒tan(α+β)=tan(2θ)
⇒
1−tanαtanβ
tanα+tanβ
=
1−tan
2
θ
2tanθ
⇒
1−m
1
.m
2
m
1
+m
2
=
1−m
2
2m
⇒
1−a/b
2h/b
=
1−m
2
2m
⇒
b−a
h
=
1−m
2
2m
⇒h(1−m
2
)=(b−a)m
⇒h(1−m
2
)−(b−a)m=0.
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