Question

If (y-3) is a factor of y³-2y²-9y=18 then find the other two factors.

Answer 1

here is your answer...
hope this helps you....

Answer 2

Answer:

(y+3) and (y-2)

Step-by-step explanation:

It is given that (y-3) is a factor of the three-degree polynomial equation y³-2y²-9y+18 =0 .......(1).

Now, we will factorize the above expression using a factor as (y-3).

Hence, y³-2y²-9y+18 =0

⇒ y³-3y²+y²-3y-6y+18 =0

⇒y²(y-3)+y(y-3)-6(y-3) =0

⇒(y-3)(y²+y-6)= 0

⇒(y-3)(y²+3y-2y-6) =0

⇒(y-3)(y+3)(y-2)=0

Hence, from the above expression, it is clear that the other two factor of equatio (1) are (y+3) and (y-2). (Answer)